apply_ifr: sort table in reverse order

This commit is contained in:
Marc Bevand
2020-09-27 13:59:16 -07:00
parent 271ef6623e
commit df929e250a
2 changed files with 214 additions and 213 deletions
+3 -3
View File
@@ -78,12 +78,12 @@ ifrs = [
(85,maxage): 22.3,
}),
# Humoral Immune Response to SARS-CoV-2 in Iceland
# Gudbjartsson et al., Humoral Immune Response to SARS-CoV-2 in Iceland
# https://www.nejm.org/doi/full/10.1056/NEJMoa2026116
# Supplementary Appendix 1
# https://www.nejm.org/doi/suppl/10.1056/NEJMoa2026116/suppl_file/nejmoa2026116_appendix_1.pdf
# (table S7)
('Iceland', {
('Gudbj', {
(0,70): 0.1,
(71,80): 2.4,
(81,maxage): 11.2,
@@ -154,7 +154,7 @@ def show_overall_ifrs(oifrs):
# (<region_name>, <ifr_according_to_1st_estimate>, <ifr_according_to_2nd_estimate>, ...)
# Sort by element index 1, that is by <ifr_according_to_1st_estimate>
# To sort by region name, use index 0 (x[0])
oifrs.sort(key=lambda x: x[1])
oifrs.sort(key=lambda x: x[1], reverse=True)
header()
for region in oifrs:
for i in region[1:]: